The value of $n$ in the molecular formula, $B e_{n} A l_{2} S i_{6} O_{18}$ is :

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Solution

The value of $n$ in the molecular formula, $B e_{n} A l_{2} S i_{6} O_{18}$ is $3$ .
The name of the compound is Beryl. It is ring silicate in which two oxygen atoms are shared per tetrahedron.

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