The value of p and qp≠0,q≠0 for which p,q are the roots of the equation: x2+px+q=0 are
p = -1, q =2
It is given that p and qp≠0,q≠0 are the roots of the equation.
x2+px+q=0
∴ Sum of the roots p + q = -q ⇒2p+q=0 ...(i) Products of roots = pq = q ⇒q(p−1)=0
⇒p=1,q=0q≠0
Now substituting p = 1 (i), we get 2(1)+q = 0 2(1)+q=0
⇒q=−2