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Question

The value of P for which the points (–5, 1), (1, –1) and (P, –2) are collinear, is

A
4
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B
2
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C
3
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D
1
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Solution

The correct option is A 4
Points (–5, 1), (1, –1), (P, –2) are collinear.

Therefore, the area of triangle formed using these points is zero.

12|5(1+2)+1(21)+P(1+1)|=0

|53+2P|=0

P=4

Hence, the correct answer is option (a)

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