The value of p if p2- 1p is

p^2= 1p p^3=1 p=1,ω ,ω ^2 ...

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Definition of Function

The value of ...

Question

The value of $p$ if $p^{2} = \frac{1}{p}$ is

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p² - 1 =

\sec θ + \tan θ = p

(i) \sec θ = \frac{1}{2} (p + \frac{1}{p}) (ii) \tan θ = \frac{1}{2} (p - \frac{1}{p}) (iii) \sin θ = \frac{p^{2} - 1}{p^{2} + 1}

a

0, 1, 2, . . ., n

q^{n}, \frac{n}{1} q^{n - 1} p, \frac{n (n - 1)}{1.2} q^{n - 2} p^{2}, . . ., p^{n}

p + q = 1

If $c o s^{- 1} p + c o s^{- 1} q + c o s^{- 1} r = π$ then $p^{2} + q^{2} + r^{2} =$

[\begin{matrix} p & p + 1 p - 1 & p \end{matrix}]

p = 1342

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