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Question

The value of pKw at 25oC is

A
7
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B
14
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C
14
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D
1×1014
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Solution

The correct option is A 14
Solution:- (C) 14
H2OH++OH
At 25,
[H+]=[OH]=1×107mol/L
Kw=[H+][OH]
Kw=(1×107)×(1×107)=1014
Therefore,
pKw=log(1014)=14

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