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Question

The value of Planck's constant is 6.63×1034Js. The velocity of light is 3×108 m/s. If the wavenumber of a quantum of light is 2.5×107 m1, calculate its frequency.

A
7.5×1015 s1
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B
3×1015 s1
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C
11×1015 s1
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D
5×1015 s1
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Solution

The correct option is A 7.5×1015 s1
We know that, for electromagnetic radiation,

c=νλ
where, c is the velocity of light

ν=cλ

=c¯ν
(where, ¯ν is the wave number, which is the inverse of wavelength)

=3×108×2.5×107 s1
=7.5×1015 s1

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