The value of Planck's constant is 6.63×10−34Js. The velocity of light is 3×108m/s. If the wavenumber of a quantum of light is 2.5×107m−1, calculate its frequency.
A
7.5×1015s−1
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B
3×1015s−1
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C
11×1015s−1
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D
5×1015s−1
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Solution
The correct option is A7.5×1015s−1 We know that, for electromagnetic radiation,
c=νλ
where, c is the velocity of light
⇒ν=cλ
⇒=c¯ν
(where, ¯ν is the wave number, which is the inverse of wavelength)