The value of r for which 20Cr20C0+20Cr−120C1+20Cr−220C2+…+20C020Cr is maximum, is :
A
11
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B
15
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C
10
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D
20
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Solution
The correct option is D20 Let S=20Cr20C0+20Cr−120C1+20Cr−220C2+…+20C020Cr
The sum S is the coefficient of xr in the expansion of (1+x)20(x+1)20=(1+x)40 ∴S=40Cr S is maximum when r=20