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Question

The value of reaction quotient (Q), for the following cell,


Zn(s)|Zn2+(0.01 M)||Ag+(1.25 M)|Ag(s) is:

A
156
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B
125
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C
1.25×102
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D
6.4×103
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Solution

The correct option is D 6.4×103
The cell reaction is
Zn(s)Zn2+(0.01 M)+2e .....equation I

Ag++eAg(s) ×2 ......equation II

On adding equation I and II, we get-

Zn(s)+2Ag+(1.25M)Zn2+(0.01 M)+2Ag(s)

Q=[Zn2+][Ag+]2=0.01(1.25)2=6.4×103

Value of Q=6.4×103.

Hence, option D is correct.

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