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Question

The value of sec2(tan12)+cosec2(cot13)

A
5
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B
10
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C
15
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D
20
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Solution

The correct option is C 15
sec2(tan12)+cosec2(cot13)
=sec2(θ1)+csc2(θ2)
secθ1=5
cosec θ2=10
sec2(tan12)+cosec2(cot13) =5+10=15.

1101591_1048633_ans_b4ce9c82d3994dc0a258ab55b9319f9a.PNG

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