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Question

The value of sin1+sin2++sin359 is equal to

A
0
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B
1
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C
1
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D
180
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Solution

The correct option is A 0
sin1+sin2++sin359
=sin1+sin2++sin179+sin180
+sin181+sin182++sin359
=sin1+sin2++sin179+sin180
+sin(180+1)+sin(180+2)++sin(180+179)
=sin1+sin2++sin179+sin180
sin1sin2sin179 [sin(π+θ)=sinθ]

=sin1800

=0 [sin1800=0]


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