The value of sin−1⎧⎨⎩cot⎧⎨⎩sin−1√2−√34+cos−1√124+sec−1√2⎫⎬⎭⎫⎬⎭ is
A
π4
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B
π6
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C
0
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D
π2
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Solution
The correct option is A0 We have, sin−1⎧⎨⎩cot⎛⎝sin−1√2−√34+cos−1√124+sec−1√2⎞⎠⎫⎬⎭ =sin−1{cot(sin−1√3−12√2+cos−1√32+sec−1√2)} =sin−1{cot(π12+π6+π4)} =sin−1(cotπ2) =sin−10=0