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Byju's Answer
Standard XI
Mathematics
Basic Inverse Trigonometric Functions
The value of ...
Question
The value of
s
i
n
−
1
[
c
o
t
(
s
i
n
−
1
√
2
−
√
3
4
+
c
o
s
−
1
√
12
4
+
s
e
c
−
1
√
2
)
]
is
A
0
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B
π
4
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C
π
6
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D
π
2
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Solution
The correct option is
A
0
s
i
n
−
1
[
c
o
t
(
s
i
n
−
1
(
√
3
−
1
2
√
2
)
+
c
o
s
−
1
√
3
2
+
s
e
c
−
1
√
2
)
]
=
s
i
n
−
1
[
0
]
=
0
Suggest Corrections
0
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