The value of sin−1(sin(17π4))+cos−1(cos(27π5))+tan−1(tan(37π6)) is
A
50π51
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
61π60
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
71π70
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
41π40
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B61π60 Let y=sin−1(sin(17π4))+cos−1(cos(27π5))+tan−1(tan(37π6))
Now, sin(17π4)=sin(4π+π4)=sinπ4 and cos(27π5)=cos(6π−3π5)=cos3π5 and tan(37π6)=tan(6π+π6)=tanπ6