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Question

The value of sin1x+cos1x,x[1,1] is

A
π2
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B
5π3
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C
3π2
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D
π
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Solution

The correct option is A π2
Consider the right angle triangle ABC, C=π2
and hypotenuse AC=1 unit
A+B+C=π
θ+π2+ϕ=π
θ+ϕ=π2 .........eq(i)
sinθ=xandcosϕ=x
θ=sin1xandϕ=cos1x ..........eq(ii)
using eq (i) and (ii)
sin1x+cos1x=π2

1527684_53131_ans_f90070aa1a8f4acfb614c92bd03478ca.png

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