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Question

The value of sin26+sin212+sin218++sin284+sin290
is

A
0
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B
7
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C
8
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D
9
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Solution

The correct option is C 8
Given,
sin26+sin212+sin218++sin284+sin290=(sin26+sin284)+(sin212+sin278) +(sin218+sin272)++(sin242+sin248) +sin290=(sin26+cos26)+(sin212+cos212) +(sin218+cos218)++(sin242+cos242)+1=7(1)+1=8

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