The value of ${sin}^{2} 60^{0} + tan 45^{0} - {cosec}^{2} 45^{0}$ is

- \frac{1}{2}

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- \frac{1}{4}

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\frac{1}{4}

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\frac{1}{2}

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Solution

The correct option is B $- \frac{1}{4}$
${sin}^{2} 60^{0} + tan 45^{0} - {cosec}^{2} 45^{0}$
$= {(\frac{\sqrt{3}}{2})}^{2} + 1 - (\sqrt{2})^{2} = \frac{3}{4} - 1 = \frac{- 1}{4}$

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The value of sin2600+tan450−cosec2450 is

The correct option is B −14sin2600+tan450−cosec2450=(√32)2+1−(√2)2=34−1=−14

The value of ${sin}^{2} 60^{0} + tan 45^{0} - {cosec}^{2} 45^{0}$ is

The correct option is B $- \frac{1}{4}$
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$= {(\frac{\sqrt{3}}{2})}^{2} + 1 - (\sqrt{2})^{2} = \frac{3}{4} - 1 = \frac{- 1}{4}$