Question

The value of ${\sin }^2{60}^{\circ }+{\cos }^2{60}^{\circ }$ is equal to

• A. 1
• B. 2
• C. 3
• D. $0$

Answer 1

The correct option is

A. 1

${\sin }^{2}60°+{\cos }^{2}60°={\left(\frac{\sqrt{3}}{2}\right)}^2+{\left(\frac{1}{2}\right)}^2$

$\Rightarrow \frac{3}{4}+\frac{1}{4}=\frac{4}{4}=1$