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First Principle of Differentiation

The value of ...

Question

The value of ${sin}^{2} 60^{o} + tan 45^{o} - {cosec}^{2} 45^{o}$ is

A

- \frac{1}{2}

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B

- \frac{1}{4}

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C

\frac{1}{4}

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D

\frac{1}{2}

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Solution

The correct option is A $- \frac{1}{4}$
${sin}^{2} 60^{o} + tan 45^{o} - {cosec}^{2} 45^{o} = \frac{3}{4} + 1 - 2 = - \frac{1}{4}$

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Similar questions

\frac{1 + {tan}^{2} 30^{o}}{1 - {tan}^{2} 30^{o}} + {csc}^{2} 60^{0} - {cos}^{2} 45^{o} + {sin}^{2} 45^{o} + \frac{1 + {cot}^{2} 60^{o}}{1 - {cot}^{2} 60^{o}}

Q. Find the value of :

{3 t a n}^{2} 30^{\circ} + \frac{4}{3} {c o s}^{2} 30^{o} - \frac{1}{2} {c o t}^{2} 45^{o} - \frac{2}{3} {s i n}^{2} 60^{o} + \frac{1}{8} {s e c}^{4} 60^{o}

Q. The value of the expressions

({sin}^{2} 30^{o} + {cos}^{2} 30^{o}) - ({sin}^{2} 60^{o} + {cos}^{2} 60^{o}) + ({sin}^{2} 45^{o} + {cos}^{2} 45^{o})

=

Q. Find the value of the following:

\frac{sin 30^{o} + tan 45^{o} - csc 60^{o}}{sec 30^{o} + cos 60^{o} + cot 45^{o}}

\frac{sin 30^{o} + tan 45^{o} - csc 60^{o}}{cot 45^{o} + cos 60^{o} - sec 30^{o}}

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