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Question

The value of sin2π4+sin23π4+sin25π4+sin27π4 is

A
0
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B
1
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C
2
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D
12
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Solution

The correct option is C 2
Given
sin2π4+sin23π4+sin25π4+sin27π4
=sin2π4+sin2(ππ4)+sin2(π+π4)+sin2(2ππ4)=sin2π4+sin2π4+(sinπ4)2+(sinπ4)2=4sin2π4=2

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