1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard XII
Mathematics
Sign of Trigonometric Ratios in Different Quadrants
The value of ...
Question
The value of
sin
2
π
6
+
cos
2
π
3
−
tan
2
π
4
+
cot
2
π
2
is equal to
A
−
1
2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
√
3
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is
A
−
1
2
sin
2
π
6
+
cos
2
π
3
−
tan
2
π
4
+
cot
2
π
2
=
(
1
2
)
2
+
(
1
2
)
2
−
(
1
)
2
+
0
=
−
1
2
Suggest Corrections
0
Similar questions
Q.
Prove that
sin
2
π
6
+
cos
2
π
3
−
tan
2
π
4
=
−
1
2
Q.
Prove that
sin
2
π
6
+
cos
2
π
3
−
tan
2
π
4
=
−
1
2
.
Q.
Show that
i)
sin
π
6
cos
0
+
sin
π
4
cos
π
4
+
sin
π
3
cos
π
6
=
7
4
ii)
sin
2
π
6
+
cos
2
π
3
−
tan
2
π
4
=
−
1
2
Q.
The value of
4
cos
2
π
3
+
sec
2
π
6
−
sin
2
π
4
is
Q.
If
⎡
⎣
cos
2
π
3
−
sin
2
π
3
sin
2
π
3
cos
2
π
3
⎤
⎦
k
=
[
1
0
0
1
]
, then least value of
k
equals
(
k
≠
0
)
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Trigonometric Functions in a Unit Circle
MATHEMATICS
Watch in App
Explore more
Sign of Trigonometric Ratios in Different Quadrants
Standard XII Mathematics
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app