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Question

The value of sin215+sin230+sin245+sin260+sin275 is

A
1
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B
32
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C
52
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D
3
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Solution

The correct option is C 52
(sin2750+sin2(150))+(sin2300+sin2600)+sin2450
=(cos2150+sin2150)+(cos2600+sin2600)+12
=1+1+12
=2+12
=52

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