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Question

The value of sin2q.cos2q(sec2q+cosec2q) is

A
2
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B
4
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C
1
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D
0
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Solution

The correct option is C 1
Given: sin2qcos2q(sec2q+cosec2q)
=sin2qcos2q(1cos2q+1sin2q)

=sin2qcos2q(sin2q+cos2qsin2qcos2q)

=sin2q+cos2q=1

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