The value of sin 4-8-sin 43 -8-sin 45 -8-sin 4-8 is

The correct option is D 32sin^4π/8+sin^43π/8+sin^45π/8+sin^47π/8 =2sin^4π/8+2cos^4π/8 =2(1 2sin^2π/8cos^2π/8) =2(1 1/2sin^2π/4) =2(1 1/4) =3/2 ...

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Trigonometric Ratios for Sum of Two Angles

The value of ...

Question

The value of ${sin}^{4} \frac{π}{8} + {sin}^{4} \frac{3 π}{8} + {sin}^{4} \frac{5 π}{8} + {sin}^{4} \frac{7 π}{8}$ is

\frac{\sqrt{3}}{4}

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\frac{3}{4}

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\frac{\sqrt{5}}{4}

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\frac{3}{2}

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s i n^{4} \frac{π}{8} + s i n^{4} \frac{3 π}{8} + s i n^{4} \frac{5 π}{8} + s i n^{4} \frac{7 π}{8} =

{sin}^{4} \frac{π}{8} + {sin}^{4} \frac{3 π}{8} + {sin}^{4} \frac{5 π}{8} + {sin}^{4} \frac{7 π}{8}

{sin}^{4} \frac{π}{8} + {sin}^{4} 3 \frac{π}{8} + {sin}^{4} 5 \frac{π}{8} + {sin}^{4} 7 \frac{π}{8} = \frac{3}{2}

{sin}^{4} \frac{π}{8} + {sin}^{4} \frac{3 π}{8} + {sin}^{4} \frac{5 π}{8} + {sin}^{4} \frac{7 π}{8} = \frac{3}{2}

{sin}^{4} \frac{π}{16} + {sin}^{4} \frac{3 π}{16} + {sin}^{4} \frac{5 π}{16} + {sin}^{4} \frac{7 π}{16}

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