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Question

The value of sin4π8+sin43π8+sin45π8+sin47π8 is
  1. 34
  2. 34
  3. 54
  4. 32


Solution

The correct option is D 32
sin4π8+sin43π8+sin45π8+sin47π8=2sin4π8+2cos4π8=2(12sin2π8cos2π8)=2(112sin2π4)=2(114)=32

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