The value of sin6θ+cos6θ+3sin2θ.cos2θ is
(sin2θ+cos2θ)3=1
sin6θ+cos6θ+3sin2θcos2θ(sin2θ+cos2θ)=1
sin6θ+cos6θ+3sin2θcos2θ(1)=1
Hence answer is C
If sinθ cosθ=12,then what is the value of sin6θ+cos6θ ?