The value of sin 60- - cos 30- is

The correct option is C 0 sin 60 #176; cos 30 #176; =√( 3 ) #160; 2 √( 3 ) #160; 2 =0 Hence, the answer is 0. ...

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Standard Values of Trigonometric Ratios

The value of ...

Question

The value of $sin 60^{\circ} - cos 30^{\circ}$ is

0

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\frac{1}{\sqrt{2}}

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\frac{\sqrt{3}}{2}

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1

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\frac{c o s 30^{\circ} + s i n 60^{\circ}}{1 + c o s 60^{\circ} + s i n 30^{\circ}} = \frac{\sqrt{3}}{2}

sin 30^{\circ} = 1 / 2

cos 30^{\circ} = \sqrt{3} / 2

sin 60^{\circ}, sin 120^{\circ}, sin 240^{\circ}, sin 300^{\circ}

sin (- 30^{\circ})

Show that:

(i) $\frac{1 - sin 60^{\circ}}{cos 60^{\circ}} = \frac{tan 60^{\circ} - 1}{tan 60^{\circ} + 1}$

(ii) $\frac{cos 30^{\circ} + sin 60^{\circ}}{1 + sin 30^{\circ} + cos 60^{\circ}} = cos 30^{\circ}$

\frac{1 - \sin 60 °}{\cos 60 °} = \frac{\tan 60 ° - 1}{\tan 60 ° + 1}

\frac{\cos 30 ° + \sin 60 °}{1 + \sin 30 ° + \cos 60 °} = \cos 30 °

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