Question

The value of $\sin \left({\cos }^{-1}\frac{3}{5}\right)$

Answer 1

$\sin \left({\cos }^{-1}\frac{3}{5}\right)$

$\therefore \cos \theta =\frac{3}{5}\Rightarrow \sin \theta =\sqrt{1-{\cos }^2\theta }=\frac{4}{5}$

$=\sin \left({\sin }^{-1}\frac{4}{5}\right)$

$=\frac{4}{5}$