the value of sin theta.sin(90-theta) -cos (90-theta) ?

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Solution

$\sin (90 - θ) - \cos (90 - θ) = \cos θ - \sin θ$

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\sin θ \cos (90 ° - θ) + \cos θ \sin (90 ° - θ)

Find the value of
$s i n θ$ $c o s θ$ [ $s i n (90^{\circ} - θ)$ $c o s e c θ$ + $c o s (90^{\circ} - θ)$ $s e c θ$ ]

\frac{sin θ cos (90^{o} - θ) cos θ}{sin (90^{o} - θ)} + \frac{cos θ sin (90^{o} - θ) sin θ}{cos (90^{o} - θ)}

\frac{c o s θ}{s i n (90 + θ)} + \frac{s i n (- θ)}{s i n (180 + θ)} + \frac{t a n (90 + θ)}{c o t θ}

sin (90 - θ) . cos θ + sin θ . cos (90 - θ)

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