The value of ${sin}^{2} {60°+cos}^{2} 60°$ is equal to

$2$

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$1$

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$3$

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$0$

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Solution

The correct option is B
$1$

We know the identity that ${sin}^{2} {θ+cos}^{2} θ=1$
So in this question ${sin}^{2} {60°+cos}^{2} 60°=1$ because here angle is same which is $60 °$ .
Hence option (2) is the correct answer and all other options are incorrect answers .

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The value of sin260°+cos260° is equal to

The correct option is B 1We know the identity that sin2θ+cos2θ=1So in this question sin260°+cos260°=1 because here angle is same which is 60°.Hence option (2) is the correct answer and all other options are incorrect answers .

The value of ${sin}^{2} {60°+cos}^{2} 60°$ is equal to

The correct option is B
$1$

We know the identity that ${sin}^{2} {θ+cos}^{2} θ=1$
So in this question ${sin}^{2} {60°+cos}^{2} 60°=1$ because here angle is same which is $60 °$ .
Hence option (2) is the correct answer and all other options are incorrect answers .