The value of - 1 - -1 is -

The correct option is A 1 We define √( a) #160;as the quantity #160;which is being multiplied by it self (or) squared become equal to ' a'.S ...

You visited us 2 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VIII

Mathematics

Finding the Square of a Number

The value of ...

Question

The value of $\sqrt{(- 1)} . \sqrt{(- 1)}$ is :

- 1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

+ 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\pm 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $- 1$
We define $\sqrt{- a}$ as the quantity which is being multiplied by it self (or) squared become equal to '- a'.
So $\sqrt{- a} \times \sqrt{- a} = (\sqrt{- a})^{2} = - a$
$∴ \sqrt{- 1} \times \sqrt{- 1} = - 1$

Suggest Corrections

Similar questions

Q. The value of

\lim_{x \to \infty} \frac{\sqrt{1 + x^{4}} + (1 + x^{2})}{x^{2}}

is

(a) −1
(b) 1
(c) 2
(d) none of these

$\int \frac{d x}{\sqrt{2 a x - x^{2}}}$ = $a^{n} s i n^{- 1} [\frac{x}{a} - 1]$

The value of n is

Q. The value of

(1 + i)^{6} + (1 - i)^{6}

is
[RPET 2002]

2⁷

2⁶

None of these

Q. The minimum value of

\frac{x}{\log_{e} x}

is

(a) e

(b) 1/e

(c) 1

(d) none of these

Find the value of the following equation, when the value of m = 150.

$m \times (1 - \frac{1}{2}) \times (1 - \frac{1}{3}) \times (1 - \frac{1}{4}) \times (1 - \frac{1}{5}) \times (1 - \frac{1}{6}) \dots \dots \dots \dots (1 - \frac{1}{m}) = ?$

Join BYJU'S Learning Program

The value of √(−1).√(−1) is :

The correct option is A −1We define √−a as the quantity which is being multiplied by it self (or) squared become equal to '- a'.So √−a×√−a=(√−a)2=−a∴√−1×√−1=−1

The value of $\sqrt{(- 1)} . \sqrt{(- 1)}$ is :

The correct option is A $- 1$
We define $\sqrt{- a}$ as the quantity which is being multiplied by it self (or) squared become equal to '- a'.
So $\sqrt{- a} \times \sqrt{- a} = (\sqrt{- a})^{2} = - a$
$∴ \sqrt{- 1} \times \sqrt{- 1} = - 1$