Question

The value of $\sqrt{3-2\sqrt{2}}$ is

• A. $\sqrt{2}-1$
• B. $\sqrt{2}+1$
• C. $\sqrt{3}-\sqrt{2}$
• D. $\sqrt{3}+\sqrt{2}$

Answer 1

The correct option is A

$\sqrt{2}-1$

$\sqrt{3-2\sqrt{2}}=\sqrt{2+1-2\times \sqrt{2}}$

$=\sqrt{(\sqrt{2}{)}^2+(1{)}^2-2\times \sqrt{2}\times 1}$

$\sqrt{(\sqrt{2}-1{)}^2=\sqrt{2}-1}$