The value of -3 20-4 cos 20-

The correct option is A 1√(3) cot 20^∘ 4 cos 20=√(3) cos 20^∘ 4cos20^∘ sin 20^∘/sin 20^∘=2sin60^∘ cos 20^∘ 2sin 40^∘/sin 20^∘ =sin 80^∘ sin 40^∘/sin 20^∘=2 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Mathematics

Cos(A+B)Cos(A-B)

The value of ...

Question

The value of $\sqrt{3} c o t 20^{\circ} - 4 c o s 20^{\circ}$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

-1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 1
$\sqrt{3} c o t 20^{\circ} - 4 c o s 20 = \frac{\sqrt{3} c o s 20^{\circ} - 4 c o s 20^{\circ} s i n 20^{\circ}}{s i n 20^{\circ}} = \frac{2 s i n 60^{\circ} c o s 20^{\circ} - 2 s i n 40^{\circ}}{s i n 20^{\circ}}$
$= \frac{s i n 80^{\circ} - s i n 40^{\circ}}{s i n 20^{\circ}} = \frac{2 c o s 60^{\circ} s i n 20^{\circ}}{s i n 20^{\circ}} = 1$

Suggest Corrections

Similar questions

Q. Find the value of

" 1257 + 320 " .

Q. The value of

[\begin{matrix} 3 & 2 & 0 \end{matrix}] U ⎡ ⎢ ⎣ \begin{matrix} 320 \end{matrix} ⎤ ⎥ ⎦

Q. The value of

\sqrt{3} csc 20 - sec 20

is equal to

The value of ? in $48 \sqrt{?} + 32 \sqrt{?} = 320$ is

Q. The value of

\frac{\cos^{3} 20 ° - \cos^{3} 70 °}{\sin^{3} 70 ° - \sin^{3} 20 °}

is

(a)

\frac{1}{2}

(b)

\frac{1}{\sqrt{2}}

Join BYJU'S Learning Program

The value of √3 cot 20∘−4 cos 20∘

The correct option is A 1√3 cot 20∘−4 cos 20=√3 cos 20∘−4cos20∘ sin 20∘sin 20∘=2sin60∘cos20∘−2sin40∘sin20∘ =sin 80∘−sin 40∘sin 20∘=2 cos 60∘ sin 20∘sin 20∘=1

The value of $\sqrt{3} c o t 20^{\circ} - 4 c o s 20^{\circ}$