Question

The value of $\sqrt[3]{3\frac{0.027}{0.008}}+\sqrt[3]{3\frac{-0.027}{0.008}}+2$ is

• A. 2
• B. 0
• C. 1
• D. -1

Answer 1

The correct option is A

2

Here, $\sqrt[3]{30.027}=\sqrt[3]{3\frac{27}{1000}}=\sqrt[3]{3\frac{3\times 3\times 3}{10\times 10\times 10}}=\frac{3}{10}=0.3$

Similarly

$\sqrt[3]{3-0.027}=\sqrt[3]{3\frac{-27}{1000}}=\sqrt[3]{3\frac{-3\times -3\times -3}{10\times 10\times 10}}=\frac{-3}{10}=-0.3$

and $\sqrt[3]{30.008}=\sqrt[3]{3\frac{8}{1000}}=\sqrt[3]{3\frac{2\times 2\times 2}{10\times 10\times 10}}=\frac{2}{10}=0.2$

Hence, substituting the value in equation $\sqrt[3]{3\frac{0.027}{0.008}}+\sqrt[3]{3\frac{-0.027}{0.008}}+2$ we get,

$\frac{0.3}{0.2}-\frac{0.3}{0.2}+2=2$