The value of -6-2-6-2 is equal to

The given expression is nbsp;(√(6)+√(2))(√(6) √(2)) Using identity (a+b)(a b) = a^2 b^2 we can write the above nbsp; (√(6)+√(2))(√(6) √(2)) = (√(6))^2 ...

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Byju's Answer

Standard IX

Mathematics

Visualisation of Identity 2

The value of ...

Question

The value of $(\sqrt{6} + \sqrt{2}) (\sqrt{6} - \sqrt{2})$ is equal to

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Solution

The correct option is D 4
The given expression is $(\sqrt{6} + \sqrt{2}) (\sqrt{6} - \sqrt{2})$

Using identity $(a + b) (a - b) = a^{2} - b^{2}$ we can write the above

$(\sqrt{6} + \sqrt{2}) (\sqrt{6} - \sqrt{2}) = (\sqrt{6})^{2} - (\sqrt{2})^{2}$
= $6 - 2 = 4$

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The value of (√6+√2)(√6−√2) is equal to

The correct option is D 4The given expression is (√6+√2)(√6−√2) Using identity (a+b)(a−b)=a2−b2 we can write the above (√6+√2)(√6−√2)=(√6)2−(√2)2 = 6−2=4

The value of $(\sqrt{6} + \sqrt{2}) (\sqrt{6} - \sqrt{2})$ is equal to

The correct option is D 4
The given expression is $(\sqrt{6} + \sqrt{2}) (\sqrt{6} - \sqrt{2})$

Using identity $(a + b) (a - b) = a^{2} - b^{2}$ we can write the above

$(\sqrt{6} + \sqrt{2}) (\sqrt{6} - \sqrt{2}) = (\sqrt{6})^{2} - (\sqrt{2})^{2}$
= $6 - 2 = 4$