The value of -0-16-0-4 is

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Laws of Exponents for Real Numbers

The value of ...

Question

The value of $\sqrt{\frac{0.16}{0.4}}$ is

0.2

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0.02

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0.63

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\frac{2 \sqrt{5}}{5}

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0.16 (5 x - 2) = 0.4 x + 7

If $\sqrt{0.04 \times 0.4 \times a} = 0.4 \times 0.04 \times \sqrt{b}$ , the value of $\frac{b}{a}$ is

\sqrt{0.04 \times 0.4 \times a} = 0.4 \times 0.04 \times \sqrt{b}

\frac{b}{a}

x = {log}_{0.4} (\frac{1}{3} + \frac{1}{3^{2}} + \frac{1}{3^{3}} + \infty)

{(0.16)}^{x}

\frac{1}{\sqrt{0. ¯ ¯ ¯ 2} + \sqrt{0. ¯ ¯ ¯ 4}} + \frac{1}{\sqrt{0. ¯ ¯ ¯ 4} + \sqrt{0. ¯ ¯ ¯ 6}} + \frac{1}{\sqrt{0. ¯ ¯ ¯ 6} + \sqrt{0. ¯ ¯ ¯ 8}} + \frac{1}{\sqrt{0. ¯ ¯¯¯ ¯ 10} + \sqrt{0. ¯ ¯¯¯ ¯ 12}} + \frac{1}{\sqrt{0. ¯ ¯¯¯ ¯ 12} + \sqrt{0. ¯ ¯¯¯ ¯ 14}} + \frac{1}{\sqrt{0. ¯ ¯¯¯ ¯ 14} + \sqrt{0. ¯ ¯¯¯ ¯ 16}} + \frac{1}{\sqrt{0. ¯ ¯¯¯ ¯ 16} + \sqrt{0. ¯ ¯¯¯ ¯ 18}} + . . . . . .

. . . . . . . . . . . . . . . + \frac{1}{\sqrt{0. ¯ ¯¯¯ ¯ 38} + \sqrt{0. ¯ ¯¯¯ ¯ 40}} = \frac{3}{2} (\sqrt{a} + \sqrt{b}),

\frac{1}{\sqrt{0. ¯ ¯ ¯ 2} + \sqrt{0. ¯ ¯ ¯ 4}} + \frac{1}{\sqrt{0. ¯ ¯ ¯ 4} + \sqrt{0. ¯ ¯ ¯ 6}} + \frac{1}{\sqrt{0. ¯ ¯ ¯ 6} + \sqrt{0. ¯ ¯ ¯ 8}} + \frac{1}{\sqrt{0. ¯ ¯¯¯ ¯ 10} + \sqrt{0. ¯ ¯¯¯ ¯ 12}} + \frac{1}{\sqrt{0. ¯ ¯¯¯ ¯ 12} + \sqrt{0. ¯ ¯¯¯ ¯ 14}} + \frac{1}{\sqrt{0. ¯ ¯¯¯ ¯ 14} + \sqrt{0. ¯ ¯¯¯ ¯ 16}} + \frac{1}{\sqrt{0. ¯ ¯¯¯ ¯ 16} + \sqrt{0. ¯ ¯¯¯ ¯ 18}} + . . . . . .

. . . . . . . . . . . . . . . + \frac{1}{\sqrt{0. ¯ ¯¯¯ ¯ 38} + \sqrt{0. ¯ ¯¯¯ ¯ 40}} = \frac{3}{2} (\sqrt{a} + \sqrt{b}),

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