The value of √(0.03)2+(0.21)2+(0.065)2(0.003)2+(0.021)2+(0.0065)2is:
0.1
10
102
103
104
=√(0.03)2+(0.21)2+(0.065)2(0.0310)2+(0.2110)2+(0.06510)2=√100[(0.03)2+(0.21)2+(0.065)2](0.03)2+(0.21)2+(0.065)2=√100=10.
Question 5 (e)
Write of the following decimal in words:
0.032
A 0.20 M solution of methanoic acid has a degree of dissociation 0.032. Its dissociation constant is: