The value of standard enthalpy of formation of SF6(g),S(g)andF(g)are−1100,275,80kJ/mol respectively. The average bond energy of SF6 (in kJ/mol) is (Give your answer upto two decimal points)
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Solution
SF6(g)→S(g)+6F(g) ΔHof=Hofproducts−Hofreactants ΔHof=(275+80×6)−(−1100) ΔHof=1855kJ/mol The average bond energy in SF6 will be = 1855kJ/mol6=309.16kJ/mol