wiz-icon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

The value of 13k=11sin(π4+(k1)π)6)sin(π4+kπ6) is equal to

A
33
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2(33)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2(31)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
2(23)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 2(31)
The value of
13k=11sin(π4+(k1)π6)sin(π4+kπ6)13k=12sinπ6[sin{π4+kπ6(π4+(k1)π6)}sin(π4+(k1)π6))sin(π4+kπ6)]13k=12[cot(π4+(k1)π6)cot(π4+kπ6)]=2[{cotπ4cot(π4+π6)}+{cot(π4+π6)cot(π4+2π6)}++{cot(π4+12π6)cot(π4+13π6)}]=2[cotπ4cot(π4+13π6)]=2[1cot5π12]=2[1313+1]=2[1(23)]=2(31)

flag
Suggest Corrections
thumbs-up
71
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon