wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The value of nk=1sin1(kk1k(k+1)) is

A
tan1n+π4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
tan1n
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
tan1n1π4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B tan1n
To find nk=1sin1(kk1k(k+1))

Let tk=sin1(kk1k(k+1))

=sin1(1kkk+11k+1k1k)

=sin1(1k11k+11k+111k)

tk=sin1(1k)sin1(1k+1)

Now,
nk=1sin1(kk1k(k+1))

=sin1(1)sin1(12)+sin1(12)sin1(13)+ .......sin1(1n)sin1(1n+1)

=sin1(1)sin1(1n+1)

=π2sin1(1n+1)

=cos1(1n+1)=tan1n

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Examples of Linear Equations
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon