1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard XI
Mathematics
Sum of Cosines of Angles in Arithmetic Progression
The value of ...
Question
The value of
10
∑
n
=
1
(
sin
2
n
π
11
−
cos
2
n
π
11
)
is equal to
Open in App
Solution
S
=
10
∑
n
=
1
(
sin
2
n
π
11
−
cos
2
n
π
11
)
=
(
sin
2
π
11
−
cos
2
π
11
)
+
(
sin
4
π
11
−
cos
4
π
11
)
+
(
sin
6
π
11
−
cos
6
π
11
)
+
⋯
+
(
sin
20
π
11
−
cos
20
π
11
)
=
(
sin
2
π
11
+
sin
4
π
11
+
⋯
+
sin
20
π
11
)
−
(
cos
2
π
11
+
cos
4
π
11
+
⋯
+
cos
20
π
11
)
=
sin
π
⋅
sin
10
π
11
sin
π
11
−
cos
π
⋅
sin
10
π
11
sin
π
11
=
0
+
sin
(
π
−
π
11
)
sin
π
11
=
1
Suggest Corrections
0
Similar questions
Q.
The value of
(
10
11
−
10
9
−
2
×
11
×
10
8
−
3
×
11
2
×
10
7
−
.
.
.
.
.
−
(
10
)
×
11
9
)
is equal to
Q.
The value of
16
−
|
−
7
|
−
|
11
−
22
|
is equal to
Q.
The value of
(
log
3
11
)
(
log
11
13
)
(
log
13
15
)
(
log
15
27
)
(
log
27
81
)
is equal to
Q.
If
t
a
n
(
3
π
11
)
+
4
s
i
n
(
2
π
11
)
=
λ
then the value of
λ
2
−
9
is equal to
___
Q.
The value of
10
∑
n
=
1
(
sin
2
n
π
11
−
cos
2
n
π
11
)
is equal to
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
MATHEMATICS
Watch in App
Explore more
Sum of Cosines of Angles in Arithmetic Progression
Standard XI Mathematics
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app