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Byju's Answer
Standard XI
Mathematics
Sum of Cosines of Angles in Arithmetic Progression
The value of ...
Question
The value of
10
∑
n
=
1
(
sin
2
n
π
11
−
cos
2
n
π
11
)
is equal to
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Solution
S
=
10
∑
n
=
1
(
sin
2
n
π
11
−
cos
2
n
π
11
)
=
(
sin
2
π
11
−
cos
2
π
11
)
+
(
sin
4
π
11
−
cos
4
π
11
)
+
(
sin
6
π
11
−
cos
6
π
11
)
+
⋯
+
(
sin
20
π
11
−
cos
20
π
11
)
=
(
sin
2
π
11
+
sin
4
π
11
+
⋯
+
sin
20
π
11
)
−
(
cos
2
π
11
+
cos
4
π
11
+
⋯
+
cos
20
π
11
)
=
sin
π
⋅
sin
10
π
11
sin
π
11
−
cos
π
⋅
sin
10
π
11
sin
π
11
=
0
+
sin
(
π
−
π
11
)
sin
π
11
=
1
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Sum of Cosines of Angles in Arithmetic Progression
Standard XI Mathematics
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