The value of 15∑r=015Cr(r−152)2 is
15∑r=015Crr2−1515∑r=0r15Cr+2254×215
15∑r=0r215Cr=1515∑r=1[r−1+1]x14Cr−1=15.214+15.14.213=215.60
∴ Required Sum = 2254×215+215.60−225.214