The value of $tan 0 ° + sec 0 ° + cot 90 ° + cosec 90 ° =$

2

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Solution

The correct option is A $2$
Given, the expression as: $tan 0 ° + sec 0 ° + cot 90 ° + cosec 90 °$
We know the values of these trigonometric raios as:
$tan 0^{\circ} = 0; sec 0^{\circ} = 1; cot 90^{\circ} = 0; cosec 90^{\circ} = 1$
Substituting all these , we get:
$tan 0 ° + sec 0 ° + cot 90 ° + cosec 90 ° = 0 + 1 + 0 + 1 = 2$

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