The value of tan-11-cos-1-12-sin-1-12 is equal to

The correct option is C 3π4 The value of tan^ 1(1)+cos^ 1( 12)+sin^ 1( 12) is =π4+2π3 π6 =3π4 ...

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Basic Inverse Trigonometric Functions

The value of ...

Question

The value of ${tan}^{- 1} (1) + {cos}^{- 1} (\frac{- 1}{2}) + {sin}^{- 1} (\frac{- 1}{2})$ is equal to

\frac{π}{4}

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\frac{5 π}{12}

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\frac{3 π}{4}

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\frac{13 π}{12}

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{sin}^{- 1} \frac{1}{2} + {cos}^{- 1} \frac{1}{2} + {tan}^{- 1} \frac{1}{\sqrt{3}}

(a) \frac{2 π}{3} (b) \frac{π}{2}

(c) \frac{3 π}{4} (d) \frac{5 π}{6}

{s i n}^{- 1} x, {c o s}^{- 1} x, {t a n}^{- 1} x

{t a n}^{- 1} x + {t a n}^{- 1} y = {t a n}^{- 1} \frac{x + y}{1 - x y}

x y < 1

π + {t a n}^{- 1} \frac{x + y}{1 - x y}

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{c o t}^{- 1} 9 + {c o s e c}^{1} \frac{\sqrt{41}}{4} = \frac{π}{4}

{t a n}^{- 1} \frac{1}{7} + {t a n}^{- 1} \frac{1}{13} = {t a n}^{- 1} \frac{2}{9}

{t a n}^{- 1} 2 + {t a n}^{- 1} 3 = 3 π / 4

{s i n}^{- 1} x, {c o s}^{- 1} x, {t a n}^{- 1} x

{t a n}^{- 1} x + {t a n}^{- 1} y = {t a n}^{- 1} \frac{x + y}{1 - x y}

x y < 1

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s i n (2 {t a n}^{- 1} \frac{1}{3}) + c o s ({t a n}^{- 1} 2 \sqrt{2}) = \frac{14}{15}

{s i n}^{- 1} {c o t ({s i n}^{- 1} \sqrt{(\frac{2 - \sqrt{3}}{4})} + {c o s}^{- 1} \frac{\sqrt{12}}{4} + {s e c}^{- 1} \sqrt{2})} = 0

{sin}^{- 1} (\frac{1}{2}) + {cos}^{- 1} (- \frac{1}{2})

\frac{π}{2}

{sin}^{- 1} (- \frac{1}{2}) + {cos}^{- 1} (\frac{1}{2})

\frac{π}{6}

{sin}^{- 1} (\frac{1}{2}) + {cos}^{- 1} (\frac{1}{2})

\frac{5 π}{6}

{sin}^{- 1} (1) + {cos}^{- 1} (- \frac{1}{2})

\frac{7 π}{6}

{sin}^{- 1} {cot {{sin}^{- 1} \sqrt{\frac{2 - \sqrt{3}}{4}} + {cos} \frac{\sqrt{12}}{4} + {sec}^{- 1} \sqrt{2}}}

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