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Question

The value of tan 1 tan 2 tan 3×..........×tan 89 is

A
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B
1
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C
2
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D
12
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Solution

The correct option is B 1
tan1tan2tan3×..........×tan89
=(tan1tan89)(tan2tan88)×....×tan45
=(tan1cot1)(tan2cot2)×...×tan45 [tanθ=cot(90θ) and tanθ×cotθ=1]
=1

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