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Question

The value of tan1 × tan2 × tan3 ×…...× tan 89 is .

A
0
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B
1
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C
2
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D
1/2
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Solution

The correct option is B 1

tanθcotθ=1,

tan(90°θ)=cotθ

and tan45=1

Given: tan1.tan2,tan3 .......tan88. tan89

= (tan1. tan89),(tan2. tan88).....(tan44.tan46) (tan45)

= [tan1. tan(901)] . [tan2. tan(902)]..........[tan44. tan(9044)].1

= (tan1. cot1). (tan2. cot2) ....... (tan44. cot44)

= 1


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