The value of $t a n^{2} 60^{0}$ is ?

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Solution

${tan}^{2} 60^{\circ} = (\sqrt{3})^{2} = 3$

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Similar questions

\frac{t a n^{2} 60^{0} - 2 t a n^{2} 45^{0} + s e c^{2} 30^{0}}{3 s i n^{2} 45^{0} s i n 90^{0} + c o s^{2} 60^{^{0}} c o s^{3} 0^{0}}

{tan}^{2} 30^{0} + {tan}^{2} 45^{0} + {tan}^{2} 60^{0} = m \frac{1}{3}

m

\frac{4}{{tan}^{2} 60^{0}} + \frac{1}{{cos}^{2} 30^{0}} - {sin}^{2} 90^{0}

\frac{x}{c o s 45^{0} . s i n 60^{0}} = t a n^{2} 60^{0} - t a n^{2} 30^{0}

(3 {cos}^{2} 30^{0} + {sec}^{2} 30^{0} + 2 cos 0^{0} + 3 sin 90^{0} - {tan}^{2} 60^{0})

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