wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The value of tan3A−tan2A−tanA is

A
tan3Atan2AtanA
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
tan3Atan2AtanA
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
tanAtan2Atan2Atan3AtanA
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None of there
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C tan3Atan2AtanA
tan3Atan2AtanA

Let us suppose that, tan3Atan2AtanA=K

then, tan3A.k+tan2A+tanA...(1)

we know that
tan(A+B)=tanA+tanB1tanA+tanB

tan(A+B)(1tanA+tan+B)=tanA+tanB...(2)

from (1) & (2)
tan3A=k+tan2A+tanA(1tan2AtanA)

tan3A=k+tan3A(1tan2AtanA)

tan3A=k+tan3Atan3A..tan2A.tanA

o=ktan3A.tan2A.tanA

k=tan3A.tan2A.tanA

tan3Atan2AtanA=tan3A.tan2A.tanA

So,the answer is 'A tan3A.tan2aA.TanA

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Basic Inverse Trigonometric Functions
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon