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Question

The value of
tan 48.tan 23.tan 42.tan 67 =___

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Solution

tan48.tan23.tan42.tan67

We know that cot(90θ)=tanθ

tan48.tan23.tan42.tan67
= tan48.tan23.tan(9048).tan(9023)
= tan48.tan23.cot48.cot23

We also know that tanθ×cotθ=1

tan48.tan23.cot48.cot23
=tan48.cot48.tan23.cot23
=1×1
=1


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