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Question

The value of tan α+2 tan 2α+4 tan 4α+8 tan 8α+16 cot 16α is

A
cot α
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B
cos α
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C
cot 2α
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D
tan 2α
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Solution

The correct option is A cot α
tanα+2 tan 2α+4 tan 4α+8 tan 8α+16 cot 16α
=cot α2 cot 2α+2(cot 2α2 cot 4α)+4(cot 4α2 cot 8α)
8(cot 8α2 cot 16α)+16 cot 16α
=cot α2 cot 2α+2 cot 2α4 cot 4α+4 cot 4α8 cot 8α+8 cot 8α16 cot 16α+16 cot 16α=cot α

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